Equation of the line passing through the point ( 2,3, -4) and perpendicular to XZ-plane is

The equation of the line passing through the point (3, 0, -4) and perpendicular to the plane 2x - 3y + 5z - 7 = 0 is

The vector equation of the line passing through the point (-1,5,4) and perpendicular to the plane z=0 is

Find the equation of the plane passing through the point (2,3,4) and perpendicular to the x-axis.

Find the equation of the plane passing through the point (2, -3, 1) and perpendicular to the line joining points (4, 5, 0) and (1, -2, 4).

The equation of line passing through the point (2, 3, 4) and perpendicular to plane 2x+3y+z+5=0 is

The equation of the plane passing through the point (-1, 2, 1) and perpendicular to the line joining the points (-3, 1, 2) and (2, 3, 4) is · · · · · ·

Find the equation of the plane passing through the point (2, ̶ 3, 1) and perpendicular to the line joining the points ( 4, 5, 0) and ( 1, ̶ 2, 4).

The equation of a line passing through point (2,3,-1) and perpendicular to ZX plane is

The equation of a line passing through point (2,3,-1) and perpendicular to XY plane is