At the same pressure, the rate of diffusion of a gas at `927^(@)C` will be ……………………. Times that at `27^(@)C`.

At a given temperature ad pressure, the rate of diffusion of a gas is :

At same temperature and pressure, the rate of diffusion of hydrogen gas is 3 sqrt( 3) times that of a hydrocarbon having molecular formula, C_(n) H_(2n-2) .The value of n is

At constant temperature and pressure the rate of diffusion of H_(2) gas is sqrt(15) times that of C_(n)H_(4n-2) gas. Find the value of n.

Under the same conditions of temperature and pressure, the rate of diffusion of hydrogen gas is four times that of oxygen gas-explain.

At what temperature will the rate of diffusion of N_(2) be 1.6 times the rate of diffusion of SO_(2) at 27°C?

At what temperature will the rate of diffusion of N_(2) be 1.6 times the rate of diffusion of SO_(2) at 27°C?

A perfect gas at 27^(@)C is heated at constant pressure to 327^(@)C . If original volume of gas at 27^(@)C is V, then volume at 327^(@)C is

The average velocity of an ideal gas at 27^(@)C is 0.3m sec^(-1) . The average velocity at 927^(@)C will be

The average speed of an ideal gas molecule at 27^(@)C is 0.3 m, sec^(-1) . The average speed at 927^(@)C