In an adiabatic process, the density of a diatomic gas becomes 32 times its initial value . The final pressure fo the gas is found to be n time the initial pressure . The value of n is :

An ideal gas at atmospheric pressure is adiabatically compressed so that its density becomes 32 times ofits initial value. If the final pressure of gas is 128 atmospheres, the value of gamma of the gas is :

A diatomic gas expands adiabatically so that final density is 32 times the initial density. Find pressure becomes N times of initial presurre . the value of N is:

A diatomic mass expands adiabatically so that final density is 32 times the initial density. Find pressure becomes N times of initial presurre . the value of N is:

A diatomic ideal gas is compressed adiabatically to 1/32 of its initial volume. If the initial temperature of the gas is T_i (in Kelvin) and the final temperature is aT_i , the value of a is

A diatomic ideal gas is compressed adiabatically to 1/32 of its initial volume. If the initial temperature of the gas is T_i (in Kelvin) and the final temperature is a T_i , the value of a is

A diatomic ideal gas is compressed adiabatically to 1/32 of its initial volume. If the initial temperature of the gas is T_i (in Kelvin) and the final temperature is a T_i , the value of a is

A monoatomic gas is compressed adiabatically to (1)/(4)^(th) of its original volume , the final pressure of gas in terms of initial pressure P is