यदि `sqrt(a+ib)=x+iy` तो सिद्ध कीजिए कि `sqrt(a-ib)=x-iy`

If sqrt(a+ib)=x+iy then prove that sqrt(a-ib)=x-iy

If sqrt(a+ib)=x+iy , then value of sqrt(a-ib) is:

If sqrt(a-ib) = x-iy , prove that sqrt(a+ib) =x+iy.

If sqrt(a+ib)=x+iy ,prove that sqrt(a-ib)=x-iy

यदि triangleABC में (If इन triangleABC), a = (1)/(sqrt(6)-sqrt(2)), b = (1)/(sqrt(6)+sqrt(2)), C = 60^(@) तो सिद्ध कीजिए कि (Prove that) c = (sqrt(4))/(2) .

If sqrt(a)+ib =x+iy prove that sqrt(a)-ib =x-iy

If sqrt(a)+ib=x+iy prove that sqrt(a)-ib=x-iy

If sqrt(a+ib) =x+iy then possible value of sqrt(a-ib) is-

If sqrt(a + ib) = x + iy, then possible value of sqrt(a - ib) is

If sqrt(a+ib)=x+iy, then possible value of sqrt(a-ib) is x^(2)+y^(2) b.sqrt(x^(2)+y^(2)) c.x+iydx-iy e.sqrt(x^(2)-y^(2))