` x + y = 3, `
`4 x - 3y = 26 `.

Solve the following pair of equations: x + 2y = 8 2x - 3y = 26 .

A point equidistant from the lines 4x + 3y + 10 = 0, 5 x - 12y + 26 =0 and 7 x + 24y - 50 = 0 is,

Show that the origin is equidistant from the three straight lines : 4x + 3y + 10 = 0,5x - 12y + 26 =0 and 7x + 24y = 50.

If 4x + 3y = 25 and 5x + 2y = 26 , then find the values of x and y

Find the values of (x+y ) , if (i) 3x + 4y = 11 , 4x + 3y = 10 (ii) 5x - 2y = 4 , x + 8y = 26

3x-4y = 10.4x + 3y = 5

Find the values of (x-y) , if (i) 3x + 4y = 11 , 4x + 3y = 10 (ii) 3x + 2y = 8 , 2x + 3y = 7

Solve for (x - 1)^(2) and (y + 3)^(2) , 2x^(2) - 5y^(2) - x - 27y - 26 = 3(x + y + 5) and 4x^(2) - 3y^(2) - 2xy + 2x - 32y - 16 = (x - y + 4)^(2) .

A point equidistant from the line 4x + 3y + 10 = 0, 5x-12y + 26 = 0 and 7x + 24y-50 = 0 is