Write the angle between the line `(x-1)/2=(y-2)/1=(z+3)/-2` and the plane `x+y+4=0`.

The angle between the line (x-3)/2=(y-1)/1=(z+4)/(-2) and the plane, x+y+z+5=0 is :

The angle between the line (x-1)/(2)=(y-2)/(1)=(z+3)/(-2) and the plane x+y+4=0 is equal to

Find the angle between the line (x-1)/1=(y-2)/(-1)=(z+1)/1 and the plane 2x+y-z=4.

Find the angle between the line (x-1)/1=(y-2)/(-1)=(z+1)/1 and the plane 2x+y-z=4.

Find the angle between the line (x-1)/3=(y-1)/2=(z-1)/4 and the plane 2x+y-3z+4=0.

Find the angle between the line (x-1)/3=(y-1)/2=(z-1)/4 and the plane 2x+y-3z+4=0.

Find the angle between the line (x-1)/3=(y-1)/2=(z-1)/4 and the plane 2x+y-3z+4=0.

The angle between the line (x-1)/(2)=(y-2)/(1)=(z+3)/(-1) and the plane x+y+4=0 is __

Statement 1: Let theta be the angle between the line (x-2)/(2)=(y-1)/(-3)=(z+2)/(-2) and the plane x+y-z=5. Then theta=sin^(-1)(1/sqrt(51)) statement 2: The angle between a straight line and a plane is the complement of the angle between the line and the normal to the plane.