A capacitor is connected across a battery .
a. Why done each plate receive a charge of exactly the same magnitude?
b. Is this true even if the plates are of different size?

A parallel plate capacitor is connected across a battery. Now, keeping the battery connected, a dielectric slab is inserted between the plates. In the process,

A parallel plate capacitor is connected across a battery. Now, keeping the battery connected, a dielectric slab is inserted between the plates. In the process,

A parallel plate capacitor of 6 mu F is connected across 18 V battery and charged. The battery is k = 2.1 is introduced between the plates. What will be the charge on capacitor ?

Five capacitors are connected across a battery of 5V as shown in figure (o). Calculate the potential difference across the plates of the 5muF capacitor.

Two identical parallel plate capacitors are connected in series to a battery of 100V . A dielectric slab of dielectric constant 4.0 is inserted between the plates of second capacitor. The potential difference across the capacitors will now be respectively

Two identical parallel plate capacitors are connected in series to a battery of 100V . A dielectric slab of dielectric constant 4.0 is inserted between the plates of second capacitor. The potential difference across the capacitors will now be respectively

The plates S and T of an uncharged parallel plate capacitor are connected across a battery. The battery is then disconnected and the charged plates are now connected in a system as shown in the figure. The system shown is in equilibrium. All the strings are insulating and massless. The magnitude of charge on one of the capacitor plates is: [Area of plates = A]

The plates S and T of a uncharged parallel plate capacitor are connected across a battery. The battery is then disconnected and the charged plates are now connected in a system as shown in the figure. The system shown is in equilibrium. All the strings are insulating and massless. the magnitude of charge on one of the capacitor plates is: [Area of plates = A ]