If the velocity is `vec(v) = 2 hat(i) + t^(2) hat(j) - 9 vec(k)`, then the magnitude of acceleration at t = 0 . 5 s is :

The position of a particle is given by vec(r) = 3that(i) - 4t^(2)hat(j) + 5hat(k). Then the magnitude of the velocity of the particle at t = 2 s is

If vec a=2 hat i+ hat k ,\ vec b= hat i+ hat j+ hat k , find the magnitude of vec axx vec bdot

If vec(a)= 3hat(i) + hat(j) + 2hat(k) and vec(b)= 2hat(i)-2hat(j) + 4hat(k) , then the magnitude of vec(b) xx vec(a) is

If vec a=2hat i+hat k,vec b=hat i+hat j+hat k, find the magnitude of vec a xxvec b

If vec(F ) = hat(i) +2 hat(j) + hat(k) and vec(V) = 4hat(i) - hat(j) + 7hat(k) what is vec(F) . vec(v) ?

If vec(a) = hat(i) + hat(j) + 2 hat(k) and vec(b) = 3 hat(i) + 2 hat(j) - hat(k) , find the value of (vec(a) + 3 vec(b)) . ( 2 vec(a) - vec(b)) .

If vec(F) = hat(i) + 2hat(j) + hat(k) and vec(V) = 4hat(i) - hat(j) + 7hat(k) find vec(F).vec(V)

Let vec a = hat i + hat j + hat k, vec b = hat i + 4 hat j - hat k, vec c = hat i + hat j + 2 hat k and hat s be a the unit vector the magnitude of the vector (vec a .vec s)(vec b xx vec c) + (vec b. vec s)(vec c xx vec a) + ( vec c.vec s)(vec a xx vec b) is equal to (A) 1 (B) 2 (C) 3 (D) 4

A particle travels so that its acceleration is given by vec(a)=5 cos t hat(i)-3 sin t hat(j) . If the particle is located at (-3, 2) at time t=0 and is moving with a velocity given by (-3hat(i)+2hat(j)) . Find (i) The velocity [vec(v)=int vec(a).dt] at time t and (ii) The position vector [vec(r)=int vec(v).dt] of the particle at time t (t gt 0) .