14/" यदि "tan theta+sec theta=l" तो सिद्ध करें कि "sec theta=(l^(2)+1)/(2l)

if tan theta+sec theta=l then prove that sec theta=(l^(2)+1)/(2l)

if tan theta+sec theta=l then prove that tan theta=(l^(2)+1)/(2l)

( tan theta)/( sec theta -1)-(tan theta )/( sec theta + 1)=

tan2 theta(sec8 theta-1)=tan8 theta(sec4 theta-1)

If sec theta + tan theta = 1/2 , then sec theta =………

prove that (tan theta) / (sec theta -1) = (tan theta + sec theta + 1) / (tan theta + sec theta - 1)

(tan theta+sec theta-1)/(tan theta-sec theta+1)

l tan theta+m sec theta=n,l'tan theta-m'sec theta=n' Prove [(nl'-ln')/(ml'+m'l)]^(2)=1+[(m'n+mn')/(lm'+l'm)]^(2)

(tan theta+sec theta-1)(tan theta+1+sec theta)=(2sin theta)/(1-sin theta)