If `sectheta=m, tantheta = n`, then `1/m{(m+n)+1/(m+n)}`

If sec theta = m and tan theta = n , then (1)/(m)[(m+n)+(1)/((m+n))]=

If sectheta=m and tan tehtah=n ,then 1/m((m+n)+frac(1)(m+n)) is equal to…..

If sectheta + tantheta = m, show that : sin theta = (m^(2) - 1 )/(m^(2) + 1)

If cos e ctheta-sintheta=m and sectheta-costheta=n , prove that (m^(2)n)^(2/3)+(m n^2)^(2/3)=1

If cottheta+tantheta=m and sectheta-costheta=n then (i) sintheta costheta=-m (ii) sintheta tantheta=-n (iii) (m^2n)^(2/3)-(mn^2)^(2/3)=1 (iv) (m^2n)^(1/3)+(xy^2)^(1/3)=1

If tantheta+sintheta=m,tantheta-sintheta=n , then show that m^2-n^2=4sqrt(mn) .

if tantheta+sintheta=m and tantheta-sintheta=n show that (m^2-n^2)^2=16mn

If tantheta+sintheta=m,tantheta-sintheta=n then show that m^2-n^2=4sqrt(mn)