What is `DeltaG^(@)` for the following reaction
`Cu^(+2)(aq)+2Ag(s)rarrCu(s)+2Ag`
`E_(Cu^(+2)//Cu)^(@)=0.34V E_(Ag^(+)//Ag)^(@)=0.8V`

Calculate the emf of the following cell: Cu(s)|Cu^(2+) (aq)||Ag^(+) (aq)| Ag(s) Given that, E_(Cu^(2+)//Cu)^(@)=0.34 V, E_(Ag//Ag^(+))^(@)=-0.80 V

Write the Nernst equation and calculate the emf of the following at 298K. Cu(s)|Cu^(2+)(0.13M)||Ag^+(1xx10^-4M)|Ag(s) Given E_(Cu^(2+)//Cu)^@ = 0.34V and E_(Ag^+//Ag)^@ = 0.80V

E.M.F of the cell reaction , 2Ag^(+) + Cu to 2Ag + Cu^(2+) is 0.46 V . If E_(Cu^(2+) // Cu)^(0) is | 0.34 V , E_(Ag^(+)//Ag)^(0) is

Predict whether the reaction is feasible or not Cu^(2+)(aq)+Fe(s)rarrCu(s)+Fe^(2+)(aq),E_(Cu^(2+)|Cu)^(@)=+0.34V and E_(Zn^(2+)|Zn)^(@)=-0.76V

Calculate the emf of the cell Cu(s) | Cu^(2+) (aq) || Ag^(+)(aq) | Ag(s) Given, E_((Cu^(2+))//(Cu))=+ 0.34 V, E_((Ag^(+))//( Ag)) = 0.80 V

Determine DeltaG^(@) and the value of the equilibrium constant for the following reaction occurring in an electrochemical cell at 25^(@)C . Cu(s)+2Ag^(+)(aq)rarr Cu^(2+)(aq)+2Ag(s) Given that, E_(Cu^(2+)|Cu)^(@)=0.34V and E_(Ag^(+)|Ag)^(@)=0.80V

Determine DeltaG^@ and the value of the equlibrium constant for the following reaction occurring in an electrochemical cell at 25^@C . Cu (s) + 2Ag^+ (aq) rarr Cu^(2+)(aq)+2Ag(s) Given that E_(Cu^(2+)//Cu)^@=0.34 V and E_(Ag^+//Ag)^@ =0.80V

It the reaction, 2Ag(s)+Fe^(2+)(aq)rarr2Ag^(+)(aq)+Fe(s) possible? Given : E_(Fe^(2+)|Fe)^(@)=-0.44V and E_(Ag^(+)|Ag)^(@)=+0.80V .