If center of a regular hexagon is at the origin and one of the vertices on the Argand diagram is `1+2i` , then its perimeter is `2sqrt(5)` b. `6sqrt(2)` c. `4sqrt(5)` d. `6sqrt(5)`

If center of a regular hexagon is at the origin and one of the vertices on the Argand diagram is 1+2i, then its perimeter is 2sqrt(5)b.6sqrt(2)c4sqrt(5)d.6sqrt(5)

If centre of a regular hexagon is at origin and one of the vertices on Argand diagram is 1+2i, where i=sqrt(-1) , then its perimeter is

If centre of a regular hexagon is at origin and one of the vertices on Argand diagram is 1+2i, where i=sqrt(-1) , then its perimeter is

(sqrt(6+2sqrt(5)))(sqrt(6-2sqrt(5)))

(sqrt(6)+sqrt(5)+ 1/(sqrt(6)+sqrt(5)))^2

Multiply 6sqrt(5) by 2sqrt(5) .

Multiply: 6sqrt(5) and 2sqrt(5)

The centroid of an equilateral triangle is (0, 0). If two vertices of the triangle lie on x+y=2sqrt(2), then one of them will have its coordinates. (a) (sqrt(2)+sqrt(6),sqrt(2)-sqrt(6)) (b) (sqrt(2)+sqrt(3),sqrt(2)-sqrt(3)) (c) (sqrt(2)+sqrt(5),sqrt(2)-sqrt(5)) (d) none of these

The centroid of an equilateral triangle is (0, 0). If two vertices of the triangle lie on x+y=2sqrt(2), then one of them will have its coordinates. (a) (sqrt(2)+sqrt(6),sqrt(2)-sqrt(6)) (b) (sqrt(2)+sqrt(3),sqrt(2)-sqrt(3)) (c) (sqrt(2)+sqrt(5),sqrt(2)-sqrt(5)) (d) none of these

The eccentricity of the ellipse 4x^2+9y^2=36 is a. 1/(2sqrt(3)) b. 1/(sqrt(3)) c. (sqrt(5))/3 d. (sqrt(5))/6