Fig, shows a toridal solenoidi whose cross-section is rectangular. Find the magnetic flux thorugh the winding equlals `I = 1.7 A`, the total number of turns Is `N = 1000`, the ratio of the outside diameter to the inside one is `eta = 1.6`, and the height is equal to `h = 5.0 cm`.

Figure-4.78 shows a toroidal solenoid whose cross-section is rectangular in shape. Find the magnetic flux through this cross-section if the current through the toroidal winding is I, total number of turns in winding is N, the inside and outside radii of the toroid are a and b respectively and the height of toroid is equal to h.

A rectangular toroid has 1000 turns. The ratio of the outer to inner diameter is 1.6 and its height is 5.0 cm. Find the flux through this toroid, if current passing through it is 1.7 A.

A solenoid of length 2m and of radius 1 cm has a winding carrying a current of 0.1 ampere per turn. Find the magnetic field strength inside the solenoid if the total number of turns is 2000.

An iron core shaped as a tore number of turns mean R = 250 mm . The supports a winding with the total number of turns N = 1000 . The core has a cross-cut of width b = 1.00 mm . With a current I = 0.85 A flowing through the winding, the magnetic induction in the gap is equal to B = 0.75 T . Assuming the scarttering of the magnetic flux at the grap edges to be negligible, find the permeaiility of iron under these conditions.

A small coil is introduced between the poles of an electromagnet so that its axis coincides with the magnetic field direction. The cross-sectional area of the coil is equal to S = 3.0 mm^2 , the number of turns is N = 60 . When the coil turns through 180^@ about its diameter, a galvanometer connected to the coil indicates a charge q = 4.5muC flowing through it. Find the magnetic induction magnitude between the poles, provided the total resistance of the electric circuit equals R = 40 Omega .

A small coil is introduced between the poles of an electromagnet so that its axis coincides with the magnetic field direction. The cross-sectional area of the coil is equal to S = 3.0 mm^2 , the number of turns is N = 60 . When the coil turns through 180^@ about its diameter, a galvanometer connected to the coil indicates a charge q = 4.5muC flowing through it. Find the magnetic induction magnitude between the poles, provided the total resistance of the electric circuit equals R = 40 Omega .

Calculating the magnetic moment ( in Am^2 ) of a thin wire with a current I=8A, wound tightlly on a half a tore (see figure). The diameter of the cross section of the tore is equal to d=5cm, and the number of turns is N=500.

Calculating the magnetic moment ( in Am^2 ) of a thin wire with a current I=8A, wound tightlly on a half a tore (see figure). The diameter of the cross section of the tore is equal to d=5cm, and the number of turns is N=500.

Calculating the magnetic moment ( in Am^2 ) of a thin wire with a current I=0.8A, wound tightlly on a half a tore (see figure). The diameter of the cross section of the tore is equal to d=5cm, and the number of turns is N=500.

Find the magnetic induction at the centre of a rectangular frame of wire whose diagonal is equal to d=16 cm and the angle between the diagonals is equal to phi=30^(@) , the current flowing in the frame equal to I=5.0A .