The maximum value of index of refraction of a material of a prism which allows the passage of light through it when the refracting angle of prism is A is

The maximum value of index of refraction of a material of a prism which allows the passage of light through it when the refracting angle of the prism is A , is

The maximum value of refractive index of a prism which permits the transmission of light through it when the refracting angle of the prism is 90^@, is given by

The maximum value of refractive index of a prism which permits the transmission of light through it when the refracting angl e of the prism is 90^@, is given by

The refractive index of the material of a prism is sqrt(2) and the angle of minimum deviation is 30^(@) . Calculate the value of the refracting angle of the prism.

The refractive angle of a prism is 60^(@) . What is the angle of minimum deviation, if the refractive index of the material of the prism is sqrt2 ?

(a) If the refracting angle of a prism is 60^@ and the minimum deviation is 30^@ , then find the angle of incidence. (b) A ray of light passes through an equilateral prism such that the angle of emergence is equal to the angle of incidence and each is equal to 3//4^(th) of the angle of prism. Find the angle of deviation. (c) The refracting of a prism is A and the refractive index of the material of the prism is cotA//2 . Find the angle of deviation. (d) The angle of a prism is 60^@ . What is the angle of incidence for minimum deviation? The refractive index of the material of the prism is sqrt2 .

The refractive index of the material of prism sqrt3, then the angle of minimum deviation of prism is

The refracting angle of a prism is A and the refractive index of its material is cot A//2 .For a ray of light incident on the prism,find the angle of minimum deviation in terms of A.