Calculate the magnetic moment of a thin wire with a current `I=0.8 A`, wound tightly on half a toroid (figure).the diameter of the cross-section of the tore is equal to `d=5.0 cm`,the number of turns is `N=500`.

Calculating the magnetic moment ( in Am^2 ) of a thin wire with a current I=8A, wound tightlly on a half a tore (see figure). The diameter of the cross section of the tore is equal to d=5cm, and the number of turns is N=500.

Calculating the magnetic moment ( in Am^2 ) of a thin wire with a current I=8A, wound tightlly on a half a tore (see figure). The diameter of the cross section of the tore is equal to d=5cm, and the number of turns is N=500.

Calculating the magnetic moment ( in Am^2 ) of a thin wire with a current I=0.8A, wound tightlly on a half a tore (see figure). The diameter of the cross section of the tore is equal to d=5cm, and the number of turns is N=500.

Derive an expression for the self-inductance of a toroid of circular crosssection of radius r and major radius R. Calculate the self inductance (L) of toroid for major radius(R) = 15 cm, crosssection of toroid having radius (r) = 2.0 cm and the number of turns (n) = 1200.

An iron tor suports N = 500 turns. Find the magnetic field energy if a current I = 2.0 A preoduces a magnetic flux across the tore's cross-section equal to Phi = 1.0 mWb .

A wire carrying current of 5 A is wound on a toroid in 4,000 turns, Calculate the magnetic field inside the core of toroid and outside the toroid if its inner radius is 15 cm and the outer radius is 18 cm.

Figure-4.78 shows a toroidal solenoid whose cross-section is rectangular in shape. Find the magnetic flux through this cross-section if the current through the toroidal winding is I, total number of turns in winding is N, the inside and outside radii of the toroid are a and b respectively and the height of toroid is equal to h.