The four vertices of a quadrilateral are `(1,\ 2),\ (-5,\ 6),\ (7,\ -4)` and `(k ,\ -2)` taken in order. If the area of the quadrilateral is zero, find the value of `k` .

The four vertices of a quadrilateral are (1,2) (-5,6) (7,-4) and (k,-2) taken in order. if the area of the quadrilateral is 9 sq. units find the value of k.

Four vertices of a quadrilateral are (1,2), (-5,6), (7,-4) and (k,-2) and its area is zero. Find the value of k.

The vertices of a quadrilateral are A(1,0), B(7,0), C(6,3) and D(2,3). Find it's area

Find the area of the quadrilateral whose vertices are (-3,\ 2),\ (5,\ 4),\ (7,\ -6) and (-5,\ -4)

Four vertices of a quadrilateral are (-5,-5), (2,-4), (3,2) and (-2,3). Find the area of the quadrilateral.

The vertices of quadrilateral in order are (-1,4),(5,6),(2,9) and (x,x^(2)). The area of the quadrilateral is (15)/(2)sq. Units,then find the point (x,x^(2))

If vertices of a quadrilateral are at A(-5, 7), B(-4, k), C(-1, -6) and D(4, 5) and its area is 72 sq. units. Find the value of k.

The co-ordinates of the four vertices of quadrilateral are (-2,4),(-1,2), (1, 2) and (2, 4), taken in order. The equation of the line through the vertex (-1, 2) and dividing the quadrilateral in two equal parts is: