`cosx - sin3x = cos2x`

cosx + sinx = cos2x + sin2x

The general solution of sinx - 3sin2x + sin3x = cosx - 3cos2x + cos3x is :

Prove that sin7x + sin5x + sin3x + sinx = 4cosx cos2x sin4x

Prove that cot4x(sin5x + sin3x) = 2cos4x cosx

Prove that (cos^3x - sin^3x)/(cosx - sinx) = (2 + sin2x)/2

The least difference between the roots of the equation : 4cosx(2 - 3sin^(2)x) + (cos2x + 1) = 0(0lt=xlt=pi/2) is :

Let f(x)=|[cosx, sinx, cosx],[cos2x,sin2x,2cos2x],[cos3x,sin3x,3cos3x]|. Find f'(pi/2)

Show that, sin3x + cos3x = (cosx-sinx)(1+4sinx cosx)

Show that, sin3x + cos3x = (cosx-sinx)(1+4sinx cosx)

sinx + cosx = (cos2x)/(1-sin2x)