The electric field intensity on the surface of a charged conductor is

The electric field intensity at the surface of a charged conductor is

The electric intensity on the surface of a charged conductor of area 0.5 m^(2) is 200 V/m. if the electric flux is 86.6 Nm^(2)//C , then the angle between the normal drawn to the surface and the electric intensity is

The direction of electrostatic field intensity at a point on the surface of a charged conductor is along the tangent drawn on the surface at that point . Is the statement true or false ?