An inductor of 20 H and a resistance of `10 Omega`, are connected to battery of 5 volt in series, then initial rate of change of current is :-

An inductor of 2 H and a resistance of 10Omega are connects in series with a battery of 5 V. The initial rate of change of current is

An inductor of 2 henry and a resistance of 10 ohms are connected in series with a battery of 5 volts. The initial rate of change of current is

An inductor of 5 henry and a resistance of 20 ohm are connected in series with a battery of 5 volt. The initial rate of change of current is

An inductor of 2 H and a resitance of 10Omega are conncts in series with a bttery of 5 V. The intial rate of change of current is

An inductor of inductance 2H and a resistance of 10 Omega are connected in series to an ac source of 1109 V, 60 Hz. The current in the circuit will be

A coil of self inductance 2.5 H and resistance 20 Omega is connected to a battery of emf 120 V having internal resistance of 5 Omega . Find : The current in the circuit in steady state.

A resistance of 12 Omega is connected with a battery of emf 1.5volt to have 0.1A current. What is the intemal resistahce of the battery?

A coil of inductance 0.5 henry is connected to a 18 volt battery. Calculate the initial rate of growth of current.