Let f(x) = minimum `(x+1, sqrt(1-x))" for all "x le 1.` Then the area bounded by y=f(x) and the x-axis is

Let f(x)= minimum (x+1,sqrt(1-x)) for all xle1 . Then the area bounded by y=f(x) and the x-axis is a) (7)/(3) sq. units b) 1/6 sq. units c) 11/6 sq. units d) 7/6 sq. units

Let f(x)=min (x+1,sqrt(1-x)) for all xlt=1. Then the area bounded by y=f(x) and the x-axis is (a) 7/3 sq units (b) 1/6 sq units (c) (11)/6 sq units (d) 7/6 sq units

Let f(x)=min (x+1,sqrt(1-x)) for all xlt=1. Then the area bounded by y=f(x) and the x-axis is (a) 7/3 sq units (b) 1/6 sq units (c) (11)/6 sq units (d) 7/6 sq units

Let f(x)= minimum (x+1,sqrt(1-x) for all x<=1 then the area bounded by y=f(x) and the x -axis,is

Consider f(x)= minimum (x+2, sqrt(4-x)), AA x le 4 . If the area bounded by y=f(x) and the x - axis is (22)/(k) square units, then the value of k is

Consider f(x)= minimum (x+2, sqrt(4-x)), AA x le 4 . If the area bounded by y=f(x) and the x - axis is (22)/(k) square units, then the value of k is

Let f(x)=min[tan x,cot x,1sqrt(3)] for all x in(0,(pi)/(2)) Then the area bounded by y=f (x) and the X -axis is

Let f(x)=min(x+1,sqrt(1-x))AA x le 1 . Then, the area (in sq. units( bounded by y=f(x), y=0 and x=0 from y=0 to x=1 is equal to

Let f(x)=min(x+1,sqrt(1-x))AA x le 1 . Then, the area (in sq. units( bounded by y=f(x), y=0 and x=0 from y=0 to x=1 is equal to