The voltage and current in a conductor are measured as `(50pm2)V and (5pm0.2)A` The percentage error in the calculation of resistance is

When the voltage and current in a conductor are measured as (100pm4 ) V and (5pm0.2 ) A, then the percentage of error in the calculation of resistance is

When the voltage and current in a conductor are measured as (100pm4 ) V and (5pm0.2 ) A, then the percentage of error in the calculation of resistance is

If voltage V=(100pm5) V and current I=(10pm0.2) A, the percentage error in resistance R is

If voltage V=(100pm5) V and current I=(10pm0.2) A, the percentage error in resistance R is

The resistance R=V/I Where V = (100 p5) V and I=(10 pm0.2) . The percentage error in R is

In the determination of resistance R is calculated from R =V//I where V is the reading of the voltmeter and I is the reading of the ammeter. The values obtained are V = 10 pm 0.2 V and I = 0.5 pm 0.01 A. The maximum percentage error in the measurement of resistance is

The percentage error in the measurement of the voltage V is 3% and in the measurement of the current is 2%. The percentage error in the measurement of the resistance is

The percentage error in the measurement of the voltage V is 3% and in the measurement of the current is 2%. The percentage error in the measurement of the resistance is