Knowing the electron gain enthalpy values for `O rarr O^(Ө)` and `O rarr O^(2-)` as `- 141 kJ mol^-1` and `+ 702 kJ mol^-1` respectively, how can you account for the formation of a large number of oxides having `O^(2-)` species and not `O^(Ө)` ?

Knowing the electron gain enthalpy values for O to O^(-) " and " O to O^(2-) " as " -141 " kJ mol"^(-1) " and " 702 " kJ mol"^(-1) respectively, how can you account for the formation of a large number of oxides having O^(2-) species and not O^(-) ?

Knowing the electron gain enthalpy values for O rarr O^- and O rarr O^(2-) as -141 and 702 kJ mol^-1 respectively, how can you account for the formation of a large number of oxides having O^(2-) species and not O^-

Knowing the electron gain enthalpy values for O rarr O^- and O rarr O^2- as -141 and 702 ~kJ ~mol^-1 respectively, how can you account for the formation of a large number of oxides having O^ 2- species and not O^-

Knowing the electron gain enthalphy values for OrarrO^- and O rarrO^2- as -141 and 702 kJ mol^- respectively, how can you account for the formation of a large number of oxides hav-ing O^2- species and not O^- ?

Knowing the electron gain enthalpy values for O to O^(-) and O to O^(2-) as -141 and "702 kJ mol"^(-1) respectively, how can you account for the formation of a large number of oxides having O^(2-) species and not O^(-) ?

Knowing the electron gain enthalpy values for O to O^(-) and OtoO^(2-) as -141 and 702 kJcdotmol^(-1) respectively, how can you account for the formation of a large number of oxides having O^(2-) species and not O^(-) ? (Hint: Consider lattice energy factor in the formation of compounds).