The time period of a loaded spring on earth is `6s`. On the surface of moon, the time period of the same loaded spring will be

The acceleration due to gravity on the surface of moon is 1.7 m s^(-2) . What is the time period of a simple pendulum on the surface of moon if its time period on the surface of earth is 3.5 s ? (g on the surface of earth is 9.8 m s^(-2) )

The time period of a simple pendulum on the surface of the earth is 4s. Its time period on the surface of the moon is

The time period of a simple pendulum on the surface of the earth is 4s. Its time period on the surface of the moon is

If the value of .g. on the surface of the moon is g/6, the time period of a pendulum on the surface of the moon w.r.t time period on the earth will be

The acceleration dula to gravity on the surface of moon is 1.7ms^(-2) . What is the time period of a simple pendulum on the surface of moon if its time period on the surface of earth is 3.5s ?