int(sin(log x)+cos(log-r))d

int[sin(log x)+cos(log x)]dx =

int sin(log x)dx

Integrate the following w.r.t. x: int [sin(log x) + cos(log x)] dx

int [ sin(log x) + cos(log x)] dx=........... A) x cos(log x) + c B) sin(log x) + c C) cos(log x) + c D) x sin(log x) + c

int [ sin(log x)+ cos (log x ) ] dx =

Evaluate int [sin(log x) + cos(log x)] dx

" 3."int[Sin(log x)+Cos(log x)]dx=

int_(1) ^(pi//2) (sin(log x ) + cos (log x )) dx =

int sin (log x)dx=

int sin (ln x) dx