2x-3y=4;3y-x=4

(i) 2x+3y=4;3x-y=-5

(dy)/(dx)=(2x-3y+4)/(3x+4y-5)

For each pair of linear equations given below, drawn graphs and then state, whether the lines drawn are parallel or perpendicular to each other. 2x-3y=6 3x+4y=24 x/4+y/3=1

2x+3y=4 3x-y=5

Solve:- 2x+3y=4 3x-y=-5 .

If the line kx+4y=6 passes through the point of intersection of the two lines 2x+3y=4 and 3x+4y=5, then : k=

Select the correct option from the given alternatives.If the line kx+4y=6 passes through the point of intersection of the two lines 2x+3y=4 and 3x+4y=5 ,then k=

Given four lines whose equations are x+2y-3=0,2x+3y-4=0,3x+4y-7=0 and 4x+5y-6=0 ,then the lines are

2x+3y=3 4x+5y=3

2x+3y=0 3x+4y=5