If a symmetrical bi-concave thin lens is cut into two identical halves, and they are placed in different ways as shown, then

There is symmetric bi-convex lens and it is cut in two pieces by a plane containing principal axis. If power of the original lens is 10 D then what will be the power of each part ?

There is a symmetric bi-convex lens and it is cut in two equal parts by a plane passing through the centre of lens and perpendicular to its principal axis. If power of original lens is 10 D then what will be the power of each part of the lens ?

A symmetric doule convex lens is cut in two equal parts by a plane perpendiculr to the pricipal axis. If the power of the original lens was 4D, the power of a cut lens will be

A symmetric doule convex lens is cut in two equal parts by a plane perpendiculr to the pricipal axis. If the power of the original lens was 4D, the power of a cut lens will be

A symmetric double convex lens is cut in two equal parts by a plane perpendicular to the principal axis. If the power of the original lens was 4D, the power of a cut lens will be

A symmetric doule convex lens is cut in two equal parts by a plane perpendiculr to the pricipal axis. If the power of the original lens was 4D, the power of a cut lens will be

In the figure (i) a thin lens of focal length 10cm is shown. The lens is cut into two equal parts, and the parts are arranged as shown in the figure (ii). An object AB of height 1cm is placed at distance of 7.5cm from the arrangement. The height of the final image will be: