A closed pipe of length 300 cm contains some sand. A speaker is connected at one of its ends. The frequency of the speaker at which the sand will arrange itself in 20 equidistant piles is close to (velocity of sound is 300 m/s)

A closes organ pipe of length 20 cm is sounded with a tuning fork in resonance. What is the frequency of the tuning fork? (v = 332 m/s)

If the length of a closed organ pipe is 1m and velocity of sound is 330 m/s , then the frequency for the second note is

f length of a closed organ pipe is 1 m and velocity of sound is 330 m//s , then the frequency is-

If the length of a closed organ pipe is 1m and velocity of sound is 330 m/s , then the frequency for the second note is

A cylindrical pipe of length 29.5cm closed at one end is found to be in resonance when a tuning fork of frequency 864Hz is sounded near the open end. Then the mode of vibration of the air in the pipe is (Velocity of sound in air is 340m/s.)

The length of an organ pipe closed at one end is 90 cm . Find out the frequency of the harmonic next to the fundamental . Velocity of sound in air = 300 m* s^(-1) .

Calculate the frequency of fifth harmonic of a closed organ pipe of length 50cm, if the velocity of sound in air is 330 m/s.

Calculate the frequency of fifth harmonic of a closed organ pipe of length 50cm, if the velocity of sound in air is 330 m/s.

Calculate the frequency of fifth harmonic of a closed organ pipe of length 50cm, if the velocity of sound in air is 330 m/s.