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Energy Stored in Inductor

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KirchhOFf's Law for Inductor || Energy Stored in an Inductor || Energy Density OF Magnetic Field

Energy Stored in an Indutor || Inductor in a Circuit

Assertion (A) : The electrostatic energy stored in capacitor plus magnetic energy stored in inductor will always be zero in series LCR circuit driven by ac voltage source under condition of resonance. Reason (R ) : The complete voltage of ac source appears across the resistor in a series LCR circuit driven by ac voltage source under condition of resonance.

At t = 0, switch S is closed, calculate (i) initial rate of increase of current, i.e., (di)/(dt)"at t"=0 . (ii) (di)/(dt) at time when current in the circuit is 0.5A . (iii) Current at t = 0.6 s. (iv) rate at which energy of magnetic field is increasing, rate of heat produced in resistance and rate at which energy is supplied by battery when i = 0.5 A. (v) energy stored in inductor in steady state.

At t=0 , switch S is closed, calculate (a) initial rate of increase of current i.e. (di)/(dt) at t=0 (b) (di)/(dt) at time when current in the circiut is 1A (c) current at t=0.5sec (d) rate at which energy of magnetic field is incresing, rate of heat produced in resistance and rate at which energy is supplied by battery when i=1A (e) energy stored in inductor in steady state

Energy Stored In An Inductor

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Energy Stored In An Inductor|Energy Stored In Per Unit Volume|Mutual Inductance|Mutual Inductance Of Pair Of Solenoid

Switches S_(1), S_(2) remain open and switch S_(3) remains closed for long time such that capacitor becomes fully charged and current in inductor coil becomes maximum, Now switches S_(1), S_(2) are simultaneously closed and S_(3) in simultaneously opened at t=0 Assume that battery and inductor coil are ideal Find time t gt 0 , when energy store in inductor would have minimum for the first time ?

Energy stored in an inductor is proportional to (i = current in the inductor)