In the given figure, `(AD)/(DB)=(AE)/(EC)` and `angle ADE=angle ACB`. Prove that `Delta ABC` is an isosceles triangle.

In the figure, angle D = angle E and (AD)/(DB) = (AE)/(EC) , prove that Delta BAC is an isosceles triangle

In the given figure , if AB = BC , angle BAD = angle CAE then prove that triangle ADE is an isosceles triangle .

In the figure, angle D = angle E " and " (AD)/(DB) = (AE)/(EC) , prove that BAC is an isosceles triangle.

In the given figure, angle 1 = angle 2 and (AC)/(BD)=(CB)/(CE) prove that Delta ACB~ Delta DCE .

In the adjoining figure, if in DeltaABC , (AD)/(DB)=(AE)/(EC) and if /_ADE=/_ACB , then write what type of triangle according to side DeltaABC is ?

In the given figure, AD = AE and AD^2 = BD xx EC . Prove that : triangles ABD and CAE are similar.

In the given figure, ABC is a triangle with /_EDB = /_ACB . Prove that DeltaABC ~ DeltaEBD . If BE = 6 cm, EC = 4 cm, BD = 5 cm and area of Delta BED = 9 cm^2 . Calculate the : area of Delta ABC

In the given figure,AD = AE and AD^(2)=BD xx EC prove that: triangles ABD and CAE are similar.

In the given figure, DE // BC. Prove that Delta ADE and Delta ABC are similar

In the adjacent figure, Delta ABC is right angled at C and DE bot AB . Prove that Delta ABC ~ Delta ADE and hence find the lengths of AE and DE ?