Two natural numbers a and b are selected at random. The probability that `a^(2)+b^(2)` is divisible by 7 is

Two natural numbers x and y are chosen at random. What is the probability that x^(2) + y^(2) is divisible by 5?

From 101 to 1000 natural numbers a number is taken at random.The probability that the numberis divisible by 17 is

Two non-negative integers x and y are chosen at random with replacement. The probability that x^(2)+y^(2) is divisible by 10, is

Two numbers a and b are selected from the set of natural number then the probability that a^(2)+b^(2) is divisible by 5 is

Two numbers a and b are chosen at random from the set of first 30 natural numbers. The probability that a^(2)-b^(2) is divisible by 3 is:

Two numbers a and b are chosen at random from the set {1,2,3,..,5n}. The probability that a^(4)-b^(4) is divisible by 5, is

Two numbers a and b are chosen at random from the set {1,2,3,..,3n}. The probability that a^(3)+b^(3) is divisible by 3, is