`~(p to ~q)` is true when

p wedgeq is true when :

STATEMENT-1 : p hArr ~q is true, when pis false and q is true. and STATEMENT-2 : p rArr ~q is true, when pis true and q is false, and -q ⇒ p is true, when q is false and p is true.

For any three simple statement p,q,r the statement (p ^^ q) vv (q ^^ r) is true when- (a) p and r true and p is false (b) p and r false and q is true (c) p,q,r all are false (d) q and r true p is false

A compound statement p and q is true only when

for any three propositions p,q and r, the proposition ( p ^^ q) ^^ ( q ^^ r) is true when

Suppose p and q are two statements and - p ^ q is true, then truth values of p and q are respectively

If statement (p vv-r)rarr(q^^r) is false and statement q is true then statement p is-

p vv q is false when :

p vv q is false when :