In the above problem the current amplification factor `beta` is

The current amplification factor is ……….. .

In an PNP transistor , 10^(10) holes enter the emitter in 10^(-6) s . If 2 % of holes is lost in the base , then the current amplification factor is

In a common base mode of transistor, collector current is 5.488 mA for an emitter current of 5.60mA . The value of the base current amplification factor (beta) will be :

In a common-base mode of a transistor, the collector current is 5.488 mA for an emitter current of 5.60 A. The value of the base current amplification factor (beta) will be

In a common base mode of a transition , the collector current is 5.488 mA for an emitter currect of 5.60 mA . The value of the base current amplification factor (beta) will be

In a common base mode of a transition , the collector current is 5.488 mA for an emitter currect of 5.60 mA . The value of the base current amplification factor (beta) will be

In a common base mode of a transition , the collector current is 5.488 mA for an emitter currect of 5.60 mA . The value of the base current amplification factor (beta) will be