If `A=[[cos theta,sin theta],[-sin theta,cos theta]]` and `A(adj A)=[[k,0],[0,k]]`, then k =

If A = [{:(costheta, sin theta),(-sin theta, cos theta):}] and A(adj A) = [{:(k,0),(0,k):}] , then k=……………

If A=[(-cos theta, -sin theta),(-cos theta, sin theta)] and A(adjA)=lamda[(1,0),(0,1)] then lamda is equal to

If A= [[cos theta,-sin theta],[sin theta,cos theta]] ,then Adj A is (a) [[cos theta,-sin theta],[cos theta,sin theta]] (b) [[1,0],[0,1]] (c) [[cos theta,sin theta],[-sin theta,cos theta]] (d) [[-1,0],[0,-1]]

If A=[(cos theta, sin theta, 0),(-sin theta, cos theta, 0),(0,0,1)] then

If the matrix [[cos theta,sin theta,0],[sin theta,cos theta,0],[0,0,1]] is singular then theta=

Simplify, costheta[[cos theta, sin theta],[-sin theta, cos theta]] + sin theta [[sin theta, -cos theta],[cos theta, sin theta]]

Find the inverse of A=[[cos theta,-sin theta,0sin theta,cos theta,00,0,1]]

(cos^(2)theta)/(sin theta)-cosec theta+sin theta=0

If the matrix [(cos theta, sin theta, 0),(sin theta, cos theta, 0),(0,0,1)] is singular then theta=