An oil drop 'B' has charge `1.6 xx 10^(-19)C and " mass " 1.6 xx 10^(-14)kg`. If the drop is in equilibrium position, then what will be potential difference between the plates. [The distance between the plates is 100mm]

The potential difference between the plates in Millikan's oil drop experiment is ________ volts.

A proton has a mass 1.67 xx 10^(-27) kg and charge + 1.6 xx 10^(-19) C. If the proton is accelerated through a potential difference of million volts, then the kinetic energy is

The de Borglie wavelength of a proton(charge = 1.6 xx 10^(-19) C, mass = 1.6 xx 10^(-27) kg) accelerated through a potential difference of 1 kV is

In Millikan's experiment, an oil drop of radius 10^(-4) cm remains suspended between the plates which are 1 cm apart. If the drop has charge of 5e over it, calculate the potential difference between the plates. The density of oil may be taken as 1.5 gcm^(-3) .

The de-Broglie wavelength of proton (" charge" = 1.6 xx 10^(-19)C, "mass" = 1.6 xx 10^(-27) Kg) accelerated through a potential difference of 1kV is

In the Milikan oil drop experiment the drop carries 10 electronic charges charge and a mass of 4.4 xx 10^(-15)kg . It is held almost stationary between two horizontal plate separated by 2cm. What is the potential between the plates?

A positively charged oil droplet remins stationary in the electric field between two horizontal plates separated by a distance of 1 cm . The charge on the drop is 10^(-15) C and mass of the droplet is 10^(-11) g , the potential difference between the plates and if the polarity is reversed , the instantaneous of the droplet are