Assertion : If the radius of earth is decreased kepping its constant, effective value of g may increase or decrease at pole.
Reason : Value of g on the surface of earth is given by `g= (Gm)/(R^(2))`.

Assertion : If the radius of earth is decreased keeping its mass constant, effective value of g may increase or decrease at pole. Reason : Value of g on the surface of earth is given by g= (Gm)/(R^(2)) .

If the radius of earth is reduced without changing the mass of earth then magnitude of g increases or decrease ?

The value of 'g' at a depth of 80 km will be ( Radius of earth=6400 km and value of 'g' on the surface of earth is 10 m/s^2 )

If the speed of rotation of earth decreases, then the value of g

A : If angular speed of the earth increases , the effective g will decrease at all places on earth . R: The value of 'g ' at latitude lambda is given by g ' = g - omega^(2)Rcos^(2)lambda

A : If angular speed of the earth increases , the effective g will decrease at all places on earth . R: The value of 'g ' at latitude lambda is given by g ' = g - omega^(2)Rcos^(2)lambda

The height at which the value of g is half that on the surface of the earth of radius R is

Considering earth's rotation, the value of g at the earth's surface is

Considering earth's rotation, the value of g at the earth's surface is