If the function `f:{-1,1} to{0,2},` defined by `f(x)=ax+b` is a surjection, then find a & b.

Let A={-1, 1} and B={0, 2} . If the functions f:A to B defined by f(x)=ax+b is an onto function? Find a and b.

If the function f: R -{1,-1} to A definded by f(x)=(x^(2))/(1-x^(2)) , is surjective, then A is equal to (A) R-{-1} (B) [0,oo) (C) R-[-1,0) (D) R-(-1,0)

If the function f: R -{1,-1} to A definded by f(x)=(x^(2))/(1-x^(2)) , is surjective, then A is equal to (A) R-{-1} (B) [0,oo) (C) R-[-1,0) (D) R-(-1,0)

If the function f :R rarr A given by f(x) = x^2/(x^2+1) is surjection , then find A.

If the function f: R -> A given by f(x)=(x^2)/(x^2+1) is surjection, then find Adot

If the function f: RvecA given by f(x)=(x^2)/(x^2+1) is surjection, then find Adot

If the function f: RvecA given by f(x)=(x^2)/(x^2+1) is surjection, then find Adot

If the function f: RvecA given by f(x)=(x^2)/(x^2+1) is surjection, then find Adot

If the function f: RvecA given by f(x)=(x^2)/(x^2+1) is surjection, then find Adot