The length of diameter of the circle `x^(2) + y^(2) + 4x - 7y - k = 0` is 9, find k.

The length of the diameter of the circle x^(2)+y^(2)-4x-6y+4=0 is -

The length of the diameter of the circle x^2+y^2−4x−6y+4=0

Find the equation of the diameter of the circle x^(2) + y^(2) - 4x + 6y + 9 = 0 which passes through the point (1, -2).

If the length of the tangent from (2,5) to the circle x^(2) + y^(2) - 5x +4y + k = 0 is sqrt(37) then find k.

If the length of the tangent from (2,5) to the circle x^(2) + y^(2) - 5x +4y + k = 0 is sqrt(37) then find k.

If the radius of the circle x^2+y^2+4x-2y-k=0 is 4 units find k.

If the line 2x-y + k = 0 is a diameter of the circle x^2 + y^2 + 6x - 6y + 5 = 0 , then k is:

If line 2x - y + k = 0 is a diameter of circle x^(2) + y^(2) + 6x - 6y + 5 = 0 , then k =

If the length of the tangent from (5,4) to the circle x^(2) + y^(2) + 2ky = 0 is 1 then find k.