The size of the species, `Pb,Pb^(2+), Pb^(4+)` decreases as -

The size of Pb,Pb^(2+) and Pb^(4+) decreases in the order:

Assertion (A): The size decreases as Pb gt Pb^(+2) gt Pb^(+4) Assertion (R): Z/e increases i.e force of attraction towards nucleous increases.

The wavelength of K_(a) , X-rays for lead isotopes Pb^(208),Pb^(206),Pb^(204)" are"lambda_(1),lambda_(2)" and"lambda_(3), resperctively. Then

The wavelength of K_(alpha) X-ray for lead isotopes Pb^(208), Pb^(206), Pb^(204) and lamda_(1), lamda_(2) and lamda_(3) respectively. Then

Pb^(2+) belongs to :

In group 14 of the periodic table, the oxidising power of tetravalent species decreases in the order a. Ge gt Pb gt Sn b. Ge gt Sn gt Pb c. Pb gt Ge gt Sn d. Pb gt Sn gt Ge

Write the cell reactions of the cell fored from Sn^(2+)//Sn, Pb^(2+)//Pb electrode E^(@)Sn^(2+)//Sn= -0.140V , E^(@)Pb^(2+)//Pb = -0.126V

The conversion of PbS to Pb is :