Mass and radius of a planet are two times the value of earth. What is the value of escape velocity from the surface of this planet?

The escape velocity on the surface of the earth is 11.2 km/s. If mass and radius of a planet is 4 and 2 times respectively than that of earth, what is the escape velocity from the planet ?

The escape velocity on the surface of the earth is 11.2 kms^(-1) . If mass and radius of a planet is 4 and 2 tims respectively than that of the earth, what is the escape velocity from the planet?

The escape velocity on the surface of the earth is 11.2 km//s . If the mass and radius of a planet 4 and 2 times more than that of the earth, What is escape velocity from the planet.

The escape velocity from the earth is v_e . If both the mass and the radius of a planet are twice that of the earth, then the escape velocity from that planet will be

The acceleration due to gravity on a planet is same as that on earth and its radius is four times that of earth. What will be the value of escape velocity on that planet if it is v_(e) on earth

If acceleration due to gravity on the surface of a planet is two times that on surface of earth and its radius is double that of earth. Then escape velocity from the surface of that planet in comparison to earth will be

If the radius of a planet is four times that of earth and the value of g is same for both, the escape velocity on the planet will be

If the radius of a planet is four times that of earth and the value of g is same for both, the escape velocity on the planet will be