If `A=[[1, 0, 0], [0, 1, 1], [0, -2, 4]] and A^(-1)=(1)/(6)(A^(2)+cA+dI)`, where `c, din R` and I is an identity matrix of order 3, then (c, d)=

If A=[[1,0,0],[0,1,1],[0,-2,4]] and 6A^(-1)=A^2+cA+dI . Then c+d is

If A=[[1,4,0],[5,2,6],[1,7,1]] and A^(-1)=(1)/(36)(alpha A^(2)+beta A+yI), where I is an identity matrix of order 3, then value of alpha, beta, gamma

A=([1,0,0],[0,1,1],[0,-2,4])" and if "A^(-1)=(1)/(6)[alpha A^(2)+beta A+gamma I]" when "I" is unit matrix of order "3" then the value of "alpha+beta+gamma" is "

If A = [(1,0,0),(0,1,1),(0,-2,4)] and also A^(-1)=1/6 (A^(2)+cA+dI) , where I is unit matrix , then the ordered pair (c,d) is :

If A = [(1,0,0), (0,1,1), (0, -2,4)], 6A ^ -1 = A ^ 2 + cA + dI, then (c, d) =

Let A=[(2,0,7),(0,1,0),(1,-2,1)] and B=[(-k,14k,7k),(0,1,0),(k,-4k,-2k)] . If AB=I , where I is an identity matrix of order 3, then the sum of all elements of matrix B is equal to

Let A=[(2,0,7),(0,1,0),(1,-2,1)] and B=[(-k,14k,7k),(0,1,0),(k,-4k,-2k)] . If AB=I , where I is an identity matrix of order 3, then the sum of all elements of matrix B is equal to

If A=({:(2,-1),(-1,2):}) " and " A^(2)-4A+3I=0 where I is the unit matrix of order 2, then find A^(-1) .

Consider a matrix A=[(0,1,2),(0,-3,0),(1,1,1)]. If 6A^(-1)=aA^(2)+bA+cI , where a, b, c in and I is an identity matrix, then a+2b+3c is equal to

Consider a matrix A=[(0,1,2),(0,-3,0),(1,1,1)]. If 6A^(-1)=aA^(2)+bA+cI , where a, b, c in and I is an identity matrix, then a+2b+3c is equal to