If the cube roots of unity are ` 1 , omega , omega^(2)`, then find the roots of the equation
` ( x - 1)^(3) + 8 = 0`.

If the cube roots of unity are 1,omega,omega^2, then the roots of the equation (x-1)^3+8=0 are

If the cube roots of unity are 1,omega,omega^(2) then the roots of the equation (x-1)^(3)+8=0 are

If the cube roots of unity are 1, omega, omega^(2) then the roots of the equation (x-1)^(3)+8=0 , are

If the cube roots of unity are 1, omega, omega ^(2) then the roots of the equation (x-2) ^(3)+ 27=0 are-

If the cube roots of unity are 1,omega,omega^(2), then the roots of the equation (x-1)^(3)+8=0, arte

If the cube roots of unity are 1, omega , (omega)^2 , then the roots of the equation (x-2)^3+27 = 0 are

If the cube root of unity are 1,omega,omega^(2) , then the roots of the equation (x-1)^(3)+8=0 are :

If the cube roots of unity are 1,omega,omega^(2), then the roots of the equation (x-1)^(3)+8=0 are -1,1+2 omega,1+2 omega^(2) b.-1,1-2 omega,1-2 omega^(2) c.-1,-1,-1 d.none of these