" 10."45-[28-{37-(15-?)}]=58

If 45-[28-{37-(15-.)}]=58, then * is equal to: -29(b)-19(c)19(d)29

45-[28-{37-(15-k)}]=58 the value of k is :

Find the value of k. 45 - [28 - {37 - (15 - k)}] = 58

Simplify : (1.598xx10^17)-(4.58xx10^15)

Calculate standard deviation for the following data : [{: ( Class Interval (C.I.) , Frequency (f) ) , (10-15,32), (15-20,28),(20-25,20),(25-30,16),(30-35,34),(35-40,10),(40-45,8):}]

15 16 20 28 45 70 106

28,37,64,109,172,?

Solve: 15-28