[" 9.If "sin theta+cos theta=m" and "sec theta+cosec theta=n" ,then "],[n(m+1)(m-1)=]

If sintheta +cos theta =m and sec theta + cosec theta =n then n(m+1)(m-1) equals

If sin theta+cos theta=m and sec theta+cos ec theta=n then n(m+1)(m-1) equals

If sin theta + costheta = m and sin theta - cos theta = n , then

If sin theta + costheta = m and sin theta - cos theta = n , then

If sin theta + cos thea = m and sec theta+ cosec theta = n , then n (m + 1) (m - 1) =

If sintheta +cos theta =m and sec theta + cosec theta =n then n(m+1)(m-1) equals................ A) m B) n C) 2m D) 2n

If m= sin theta+ cos theta and n= sec theta+cosec theta , prove that n (m + 1) (m-1) = 2m .

If sin theta + cos theta = m and sec theta + "cosec" theta = n, prove that n(m^(2)-1) = 2m.

If cos theta+sin theta=m and sec theta+csc theta=n,then(2m^(2))/((m^(2)-1)^(2))=?