A rod of 5 cm length is moving perpendicular to uniform magnetic field of intensity `2 xx 10^(-4) "Wbm"^(-2)`. If the acceleration of rod is `2 ms^(-2)`, the rate of increasing of the induced emf is .......

Options

A. `20xx10^(-4) Vs^(-2)`
B. `20xx10^(-4)V`
C. `20xx10^(-4)` Vs
D. `2 xx10^(-5)Vs^(-1)`

Answer

D

Explanation

The induced emf `|epsilon|=Bvl`
`therefore (d|epsilon|)/(dt)=d/(dt)(Bvl)`
`=B(dv)/(dt)l` [ `because` B and l are constant]
=Bal[`because (dv)/(dt)`=a=acceleration]
`=2xx10^(-2)xx2xx5xx10^(-2)`
`=20xx10^(-4)Vs^(-1)`