For an inductor having self inductance 4.6 H, emf induced in it for time interval from 5 ms to 6 ms is ……

Options

A. zero
B. `10^3` V
C. `-23xx10^3` V
D. `23xx10^3` V

Answer

D

Explanation

Here `(dI)/(dt)` = slope of `bar(BC)`
`=(0-5)/(1xx10^(-3))=-5xx10^3 A/s`
Now , self induced emf is,
`epsilon=-L (dI)/(dt)`
=-(4.6)`(-5xx10^3)`
`therefore epsilon=23xx10^3` V