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Current I is following through a toroida...

Current I is following through a toroidal solenoid of radius r, length l and area A. If the number of turns of toroidal solenoid is N, then energy stored in the toroidal solenoid is …..

A

`1/2 (mu_0N^2 A I^2)/(pir)`

B

`1/8 (mu_0 N^2 A I^2)/(pir)`

C

`1/6 (mu_0 N^2 AI^2)/(pir)`

D

`1/4 (mu_0N^2A I^2)/(pir)`

Text Solution

Verified by Experts

The correct Answer is:
D

Energy stored in inductor `U=1/2 LI^2` Put `L=(mu_0N^2A)/l` in `U=1/2xxL(mu_0N^2AI^2)/l`
But for toroid `l=2pir`
`therefore U=1/2xx(mu_0N^2 AI^2)/(2pir)`
`therefore U=1/4 xx (mu_0N^2AI^2)/(pir)`
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KUMAR PRAKASHAN-ELECTROMAGNETIC INDUCTION-Section D MCQs (From DARPAN Based on Textbook )
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  8. The flux linked with each turn of coil is 0.1 Wb and total number of t...

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