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Two charges are at a distance d apart. I...

Two charges are at a distance d apart. If a copper plate of thickness `d/2` is placed between them, if effective force will be,

A

2F

B

`F//2`

C

4F

D

`sqrt2 F`

Text Solution

Verified by Experts


Colombian force exerted between charges `q_1 and q_2` in the absence of copper plate,
`F=1/(4pi e_0 K) (q_1q_2)/r^2`
`therefore F=1/(4pi e_0) (q_1q_2)/d^2 (because k=1)`
Now ,as shown in the figure, after placing given copper plate, new colombian force between `q_1 and q_2` will be
`F.=1/(4pi e_0) (q_1q_2)/((sqrtK_1 r_1+sqrtK_2 r_2+sqrtK_3r_3)^2)`
Placing the values
`F.=1/(4pi e_0) (q_1q_2)/((d/4+infty+d/4)^2)=1/(4 pi e_0)(q_1q_2)/infty^2=0`
Note: Height of copper plate should be give every large otherwise electric field line emanating from `q_1` may reach `q_2` by passing above or below the copper plate.
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