The dimensional formula of `B^2/(2mu_0)` is……

Options

A. `M^-1 L^1 T^2`
B. `M^1 L^-1 T^-2`
C. `M^-1 L^-1 T^-2`
D. `M^1 L^1 T^2`

Answer

B

Explanation

Here `B^2/(2mu_0)` is electromagnetic energy density.
Hence its dimensional formula =`([energy])/([volume])`
`=(M^1L^2T^-2)/L^3=M^1L^-1T^-2`