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The output of a step down transfomer is ...

The output of a step down transfomer is measured to be 24V when connected to a 12W light bulb. The value of the peak current is……..A

A

`1/sqrt2`

B

`sqrt2`

C

2

D

`2sqrt2`

Text Solution

Verified by Experts

The correct Answer is:
A
`V_2I_2=12W` (For ideal transformer)
`therefore I_2=12/V_2=12/24=1/2A`
Now according to formula,
`I_(rms)=I_m/sqrt2`
`therefore I_m=sqrt2 I_(rms)=sqrt2 times 1/2=1/sqrt2 A`
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