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A capacitor of 250 mu F is connected par...

A capacitor of `250 mu F` is connected parallel with a inductor of 0.16mH. IF the effective resistance is `20 Omega` then resonant frequency……. Hz.

A

`9 times 10^4`

B

`16 times 10^7`

C

`8 times 10^5`

D

`9 times 10^3`

Text Solution

Verified by Experts

`f_0=1/(2pisqrt(LC))`
`therefore f_0=1/(2 times 3.14 times sqrt(0.16 times 10^-3 times 250 times 10^-6))`
`therefore f_0=1/(6.28 times sqrt(16 times 10^-5 times 25 times 10^-5))`
`therefore f_0=1/(6.28 times sqrt(400 times 10^-10))`
`therefore f_0=1/(6.28 times 20 times 10^-5)`
`therefore f_0=1/(6.28 times 20) times 10^5`
`therefore f_0=7.96 times 10^-3 times 10^5`
`therefore f_0=7.96 times 10^2 Hz`
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